$0 = (20)^2 - 2(9.8)h$
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At maximum height, $v = 0$
Given $u = 20$ m/s, $g = 9.8$ m/s$^2$
$\Rightarrow h = \frac{400}{2 \times 9.8} = 20.41$ m practice problems in physics abhay kumar pdf
Using $v^2 = u^2 - 2gh$, we get
You can find more problems and solutions like these in the book "Practice Problems in Physics" by Abhay Kumar. $0 = (20)^2 - 2(9
At $t = 2$ s, $a = 6(2) - 2 = 12 - 2 = 10$ m/s$^2$